-10x^2+36x-27=0

Solution for -10x^2+36x-27=0 equation:

-10x^2+36x-27=0

a = -10; b = 36; c = -27;
Δ = b2-4ac
Δ = 362-4·(-10)·(-27)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-6\sqrt{6}}{2*-10}=\frac{-36-6\sqrt{6}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+6\sqrt{6}}{2*-10}=\frac{-36+6\sqrt{6}}{-20}
$